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1Z0-803 - Java SE 7 Programmer I - Dump Information

Vendor	:	Oracle
Exam Code	:	1Z0-803
Exam Name	:	Java SE 7 Programmer I
Questions and Answers	:	216 Q & A
Updated On	:	November 20, 2017
PDF Download Mirror	:	1Z0-803 Brain Dump
Get Full Version	:	Pass4sure 1Z0-803 Full Version

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1Z0-803 Questions and Answers

1. A NullPointerException is thrown at runtime
2. A NumberFormatException is thrown at runtime
3. AnArrayIndexOutOfBoundException is thrown at runtime.

Answer: A

QUESTION: 207

Given the code fragment:

Boolean b1 = true; Boolean b2 = false; int i = 0;

while (foo) { } Which one is valid as a replacement for foo?

1. b1.compareTo(b2)
2. i = 1

C. i == 2? -1 : 0

D. "foo".equals("bar")

Answer: D

Explanation:

Equals works fine on strings equals produces a Boolean value.

QUESTION: 208

Given:

The class is poorly encapsulated. You need to change the circle class to compute and return the area instead. Which two modifications are necessary to ensure that the class is being properly encapsulated?

1. Remove the area field.
2. Change the getArea( ) method as follows:
   public double getArea ( ) { return Match.PI * radius * radius; }
3. Add the following method:
   public double getArea ( ) {area = Match.PI * radius * radius; }
4. Change the cacess modifier of the SerRadius ( ) method to be protected.

Answer: B, D

QUESTION: 209

Given the code fragment

Which code fragments, inserted independently, enable the code compile?

1. t.fvar = 200;
2. cvar = 400;
3. fvar = 200; cvar = 400;
4. this.fvar = 200; this.cvar = 400;
5. t.fvar = 200; Test2.cvar = 400;
6. this.fvar = 200; Test2.cvar = 400;

Answer: B

QUESTION: 210

public class StringReplace {

public static void main(String[] args) { String message = "Hi everyone!"; System.out.println("message = " + message.replace("e", "X")); }

}

What is the result?

1. message = Hi everyone!
2. message = Hi XvXryonX!
3. A compile time error is produced.
4. A runtime error is produced.
5. message =
6. message = Hi Xveryone!

Answer: B

QUESTION: 211

Given:

class Base {

// insert code here

}

public class Derived extends Base{ public static void main(String[] args) { Derived obj = new Derived(); obj.setNum(3);

System.out.println("Square = " + obj.getNum() * obj.getNum());

}

}

Which two options, when inserted independently inside class Base, ensure that the class is being properly encapsulated and allow the program to execute and print the square of the number?

1. private int num;public int getNum() {return num;}public void setNum(int num) {this.num
   = num;}
2. public int num;protected public int getNum() {return num;}protected public void setNum(int num) {this.num = num;}
3. private int num;public int getNum() {return num;}private void setNum(int num)
   {this.num
   = num;}
4. protected int num;public int getNum() {return num;}public void setNum(int num)
   {this.num = num;}
5. protected int num;private int getNum() {return num;}public void setNum(intnum)

{this.num = num;}

Answer: A, D

Explanation:

Incorrect:

Not B: illegal combination of modifiers: protected and public not C: setNum method cannot be private.not E: getNum method cannot be private.

QUESTION: 212

Given:

What is true about the class Wow?

1. It compiles without error.
2. It does not compile because an abstract class cannot have private methods.
3. It does not compile because an abstract class cannot have instance variables.
4. It does not compile because an abstract class must have at least one abstract method.
5. It does not compile because an abstract class must have a constructor with no arguments.

Answer: A

QUESTION: 213

Given:

public class DoBreak1 {

public static void main(String[] args) { String[] table = {"aa", "bb", "cc", "dd"}; for (String ss: table) {

if ( "bb".equals(ss)){ continue;} System.out.println(ss); if ( "cc".equals(ss)) { break;}

}

}

}

What is the result?

1. aa cc
2. aa bb cc
3. cc dd
4. cc
5. Compilation fails.

Answer: A

QUESTION: 214

Given: Given:

public class SuperTest {

public static void main(String[] args) { statement1 statement2 statement3

}

}

class Shape { public Shape() { System.out.println("Shape: constructor");

}

public void foo() { System.out.println("Shape: foo");

}

}

class Square extends Shape { public Square() { super();

}

public Square(String label) { System.out.println("Square: constructor");

}

public void foo() { super.foo();

}

public void foo(String label) { System.out.println("Square: foo");

}

}

}

}

Whatshould statement1, statement2, and statement3, be respectively, in order to produce the result? Shape: constructor Square: foo Shape: foo

1. Square square = new Square ("bar"); square.foo ("bar"); square.foo();
2. Square square = new Square ("bar"); square.foo ("bar"); square.foo ("bar");
3. Square square = new Square (); square.foo (); square.foo(bar);
4. Square square = new Square (); square.foo (); square.foo("bar");
5. Square square = new Square (); square.foo (); square.foo ();
6. Square square = newSquare(); square.foo("bar"); square.foo();

Answer: F

QUESTION: 215

Given:

public class Marklist { int num;

public static void graceMarks(Marklist obj4) { obj4.num += 10;

}

public static void main(String[] args){ MarkList obj1 = new MarkList(); MarkList obj2 = obj1;

MarkList obj1 = null; obj2.num = 60; graceMarks(obj2);

}

}

How many objects are created in the memory runtime?

1. 1
2. 2
3. 3
4. 4

Answer: B

Explanation:

obj1 and obj3.

when you do e2 = e1you're copying object references - you're not making a copy of the object - and so the variables e1 and e2 will both point to the same object.

QUESTION: 216

Given the class definitions:

And the code fragment of the main() method,

What is the result?

1. Java Java Java
2. Java Jeve va
3. Java Jeve ve
4. Compilation fails

Answer: D

Oracle 1Z0-803 Exam (Java SE 7 Programmer I) Detailed Information

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